What is the derivative of 0.8x^2-3x+5x^{0.2}-5200 ?

The derivative of 0.8x^2-3x+5x^{0.2}-5200 is 1.6x+1/(x^{0.8)}-3

What is the first derivative of 0.8x^2-3x+5x^{0.2}-5200 ?

The first derivative of 0.8x^2-3x+5x^{0.2}-5200 is 1.6x+1/(x^{0.8)}-3

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\frac{d}{d x} (0.8 x^{2} - 3 x + 5 x^{0.2} - 5200)

1.6 x + \frac{1}{x ^{0.8}} - 3

Solution steps

\frac{d}{d x} (0.8 x^{2} - 3 x + 5 x^{0.2} - 5200)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (0.8 x^{2}) - \frac{d}{d x} (3 x) + \frac{d}{d x} (5 x^{0.2}) - \frac{d}{d x} (5200)

\frac{d}{d x} (0.8 x^{2}) = 1.6 x

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (5 x^{0.2}) = \frac{1}{x ^{0.8}}

\frac{d}{d x} (5200) = 0

= 1.6 x - 3 + \frac{1}{x ^{0.8}} - 0

Simplify

= 1.6 x + \frac{1}{x ^{0.8}} - 3

What is the derivative of 0.8x^2-3x+5x^{0.2}-5200 ?
The derivative of 0.8x^2-3x+5x^{0.2}-5200 is 1.6x+1/(x^{0.8)}-3
What is the first derivative of 0.8x^2-3x+5x^{0.2}-5200 ?
The first derivative of 0.8x^2-3x+5x^{0.2}-5200 is 1.6x+1/(x^{0.8)}-3