What is the derivative of f(x)=2x^2+3x-9 ?

The derivative of f(x)=2x^2+3x-9 is 4x+3

What is the first derivative of f(x)=2x^2+3x-9 ?

The first derivative of f(x)=2x^2+3x-9 is 4x+3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

derivative of

f (x) = 2 x^{2} + 3 x - 9

4 x + 3

Solution steps

\frac{d}{d x} (2 x^{2} + 3 x - 9)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{2}) + \frac{d}{d x} (3 x) - \frac{d}{d x} (9)

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (9) = 0

= 4 x + 3 - 0

Simplify

= 4 x + 3

What is the derivative of f(x)=2x^2+3x-9 ?
The derivative of f(x)=2x^2+3x-9 is 4x+3
What is the first derivative of f(x)=2x^2+3x-9 ?
The first derivative of f(x)=2x^2+3x-9 is 4x+3