What is the integral from 1 to 2 of x^2+1/(4x^2) ?

The integral from 1 to 2 of x^2+1/(4x^2) is 59/24

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integral from 1 to 2 of x^2+1/(4x^2)

\int_{1}^{2} x^{2} + \frac{1}{4 x ^{2}} d x

\frac{59}{24}

Decimal

2.45833 \dots

Solution steps

\int_{1}^{2} x^{2} + \frac{1}{4 x ^{2}} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{2} x^{2} d x + \int_{1}^{2} \frac{1}{4 x ^{2}} d x

\int_{1}^{2} x^{2} d x = \frac{7}{3}

\int_{1}^{2} \frac{1}{4 x ^{2}} d x = \frac{1}{8}

= \frac{7}{3} + \frac{1}{8}

Simplify

\frac{7}{3} + \frac{1}{8} : \frac{59}{24}

= \frac{59}{24}

What is the integral from 1 to 2 of x^2+1/(4x^2) ?
The integral from 1 to 2 of x^2+1/(4x^2) is 59/24