What is the derivative of (x^2/(16)) ?

The derivative of (x^2/(16)) is x/8

What is the first derivative of (x^2/(16)) ?

The first derivative of (x^2/(16)) is x/8

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\frac{d}{d x} (\frac{x ^{2}}{16})

\frac{x}{8}

Solution steps

\frac{d}{d x} (\frac{x ^{2}}{16})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{16} \frac{d}{d x} (x^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{1}{16} \cdot 2 x^{2 - 1}

Simplify

\frac{1}{16} \cdot 2 x^{2 - 1} : \frac{x}{8}

= \frac{x}{8}

What is the derivative of (x^2/(16)) ?
The derivative of (x^2/(16)) is x/8
What is the first derivative of (x^2/(16)) ?
The first derivative of (x^2/(16)) is x/8