What is the integral of (e^{y^3+2}) ?

The integral of (e^{y^3+2}) is e^2(-(y\Gamma(1/3 ,-y^3))/(3\sqrt[3]{-y^3)})+C

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integral of (e^{y^3+2})

\int (e^{y^{3} + 2}) d y

Solution steps

\int e^{y^{3} + 2} d y

e^{y^{3} + 2} = e^{2} e^{y^{3}}

= \int e^{2} e^{y^{3}} d y

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= e^{2} \cdot \int e^{y^{3}} d y

Use the nonelementary integral:

Add a constant to the solution

What is the integral of (e^{y^3+2}) ?
The integral of (e^{y^3+2}) is e^2(-(y\Gamma(1/3 ,-y^3))/(3\sqrt[3]{-y^3)})+C