What is the solution for y^'=sqrt(xy) ?

The solution for y^'=sqrt(xy) is y=(x^3)/9+(c_{1}x^{3/2})/3+(c_{1}^2)/4

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y^'=sqrt(xy)

y^{^{'}} = x y

y = \frac{x ^{3}}{9} + \frac{c _{1} x ^{\frac{3}{2}}}{3} + \frac{c _{1}^{2}}{4}

Solution steps

y^{'} (x) = x y

Solve separable ODE:

y = \frac{x ^{3}}{9} + \frac{c _{1} x ^{\frac{3}{2}}}{3} + \frac{c _{1}^{2}}{4}

y = \frac{x ^{3}}{9} + \frac{c _{1} x ^{\frac{3}{2}}}{3} + \frac{c _{1}^{2}}{4}

What is the solution for y^'=sqrt(xy) ?
The solution for y^'=sqrt(xy) is y=(x^3)/9+(c_{1}x^{3/2})/3+(c_{1}^2)/4