What is the solution for y^{''}+5(dy)/(dx)+6y=2e^x ?

The solution for y^{''}+5(dy)/(dx)+6y=2e^x is y=c_{1}e^{-2x}+c_{2}e^{-3x}+1/6 e^x

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y^{''}+5(dy)/(dx)+6y=2e^x

y^{^{''}} + 5 \frac{d y}{d x} + 6 y = 2 e^{x}

y = c_{1} e^{- 2 x} + c_{2} e^{- 3 x} + \frac{1}{6} e^{x}

Solution steps

y^{''} (x) + 5 y^{'} (x) + 6 y = 2 e^{x}

Solve linear ODE:

y = c_{1} e^{- 2 x} + c_{2} e^{- 3 x} + \frac{1}{6} e^{x}

y = c_{1} e^{- 2 x} + c_{2} e^{- 3 x} + \frac{1}{6} e^{x}

What is the solution for y^{''}+5(dy)/(dx)+6y=2e^x ?
The solution for y^{''}+5(dy)/(dx)+6y=2e^x is y=c_{1}e^{-2x}+c_{2}e^{-3x}+1/6 e^x