What is the integral of e^{x^1} ?

The integral of e^{x^1} is -(x\Gamma(1/1 ,-x^1))/(1*(-x^1)^{1/1)}+C

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integral of e^{x^1}

\int e^{x^{1}} d x

- \frac{x Γ ( \frac{1}{1} , - x ^{1} )}{1 \cdot ( - x ^{1} ) ^{\frac{1}{1}}} + C

Solution steps

\int e^{x^{1}} d x

Use the nonelementary integral:

= - \frac{x Γ ( \frac{1}{1} , - x ^{1} )}{1 \cdot ( - x ^{1} ) ^{\frac{1}{1}}}

Add a constant to the solution

= - \frac{x Γ ( \frac{1}{1} , - x ^{1} )}{1 \cdot ( - x ^{1} ) ^{\frac{1}{1}}} + C

What is the integral of e^{x^1} ?
The integral of e^{x^1} is -(x\Gamma(1/1 ,-x^1))/(1*(-x^1)^{1/1)}+C