derivative x^2-2x+8

解答

导数

x^{2} - 2 x + 8

2 x - 2

求解步骤

\frac{d}{d x} (x^{2} - 2 x + 8)

使用微分加减法定则:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) - \frac{d}{d x} (2 x) + \frac{d}{d x} (8)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (8) = 0

= 2 x - 2 + 0

化简

= 2 x - 2