integral from 0 to 33 of 3(x-1)^{-1/5}

解

\int_{0}^{33} 3 (x - 1)^{- \frac{1}{5}} d x

\frac{225}{4}

十進法表記

56.25

解答ステップ

\int_{0}^{33} 3 (x - 1)^{- \frac{1}{5}} d x

未定義の (特異) 点を求める:

x = 1

存在する場合は

b, a < b < c, f (b) =

未定義

, \int_{a}^{c} f (x) d x = \int_{a}^{b} f (x) d x + \int_{b}^{c} f (x) d x

= \int_{0}^{1} 3 (x - 1)^{- \frac{1}{5}} d x + \int_{1}^{33} 3 (x - 1)^{- \frac{1}{5}} d x

\int_{0}^{1} 3 (x - 1)^{- \frac{1}{5}} d x = - \frac{15 ( - 1 ) ^{\frac{4}{5}}}{4}

\int_{1}^{33} 3 (x - 1)^{- \frac{1}{5}} d x = 60

= - \frac{15 ( - 1 ) ^{\frac{4}{5}}}{4} + 60

簡素化

- \frac{15 ( - 1 ) ^{\frac{4}{5}}}{4} + 60 : \frac{225}{4}

= \frac{225}{4}