What is the solution for y^{''}-2/7 y^'+1/49 y=0 ?

The solution for y^{''}-2/7 y^'+1/49 y=0 is y=c_{1}e^{t/7}+c_{2}e^{t/7}t

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y^{''}-2/7 y^'+1/49 y=0

y^{^{''}} - \frac{2}{7} y^{^{'}} + \frac{1}{49} y = 0

y = c_{1} e^{\frac{t}{7}} + c_{2} e^{\frac{t}{7}} t

Solution steps

y^{''} (t) - \frac{2}{7} y^{'} (t) + \frac{1}{49} y = 0

Solve linear ODE:

y = c_{1} e^{\frac{t}{7}} + c_{2} e^{\frac{t}{7}} t

y = c_{1} e^{\frac{t}{7}} + c_{2} e^{\frac{t}{7}} t

What is the solution for y^{''}-2/7 y^'+1/49 y=0 ?
The solution for y^{''}-2/7 y^'+1/49 y=0 is y=c_{1}e^{t/7}+c_{2}e^{t/7}t