What is the integral of 2/(sqrt(3+2x)) ?

The integral of 2/(sqrt(3+2x)) is 2sqrt(3+2x)+C

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integral of 2/(sqrt(3+2x))

\int \frac{2}{3 + 2 x} d x

2 3 + 2 x + C

Solution steps

\int \frac{2}{3 + 2 x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int \frac{1}{3 + 2 x} d x

Apply u-substitution

= 2 \cdot \int \frac{1}{2 u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \frac{1}{2} \cdot \int \frac{1}{u} d u

Apply the Power Rule

= 2 \cdot \frac{1}{2} \cdot 2 u^{\frac{1}{2}}

Substitute back

u = 3 + 2 x

= 2 \cdot \frac{1}{2} \cdot 2 (3 + 2 x)^{\frac{1}{2}}

Simplify

2 \cdot \frac{1}{2} \cdot 2 (3 + 2 x)^{\frac{1}{2}} : 2 3 + 2 x

= 2 3 + 2 x

Add a constant to the solution

= 2 3 + 2 x + C

What is the integral of 2/(sqrt(3+2x)) ?
The integral of 2/(sqrt(3+2x)) is 2sqrt(3+2x)+C