What is the derivative of 2ax+b/x ?

The derivative of 2ax+b/x is 2a-b/(x^2)

What is the first derivative of 2ax+b/x ?

The first derivative of 2ax+b/x is 2a-b/(x^2)

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derivative of

2 a x + \frac{b}{x}

2 a - \frac{b}{x ^{2}}

Solution steps

\frac{d}{d x} (2 a x + \frac{b}{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 a x) + \frac{d}{d x} (\frac{b}{x})

\frac{d}{d x} (2 a x) = 2 a

\frac{d}{d x} (\frac{b}{x}) = - \frac{b}{x ^{2}}

= 2 a - \frac{b}{x ^{2}}

What is the derivative of 2ax+b/x ?
The derivative of 2ax+b/x is 2a-b/(x^2)
What is the first derivative of 2ax+b/x ?
The first derivative of 2ax+b/x is 2a-b/(x^2)