What is the tangent of f(x)=(x^7)/7-7/(x^7),\at x=-1 ?

The tangent of f(x)=(x^7)/7-7/(x^7),\at x=-1 is y=50x+398/7

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tangent of f(x)=(x^7)/7-7/(x^7),\at x=-1

tangent of

f (x) = \frac{x ^{7}}{7} - \frac{7}{x ^{7}}, at x = - 1

y = 50 x + \frac{398}{7}

Solution steps

Find the tangent point:

(- 1, \frac{48}{7})

Find the slope of

f (x) = \frac{x ^{7}}{7} - \frac{7}{x ^{7}} : \frac{df ( x )}{d x} = x^{6} + \frac{49}{x ^{8}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 50

Find the line with slope m=

50

and passing through

(- 1, \frac{48}{7}) : y = 50 x + \frac{398}{7}

y = 50 x + \frac{398}{7}

What is the tangent of f(x)=(x^7)/7-7/(x^7),\at x=-1 ?
The tangent of f(x)=(x^7)/7-7/(x^7),\at x=-1 is y=50x+398/7