derivative ln(x^2+y^2)

解答

导数

ln (x^{2} + y^{2})

\frac{2 x}{x ^{2} + y ^{2}}

求解步骤

\frac{d}{d x} (ln (x^{2} + y^{2}))

将

y

视为常数

使用连锁律:

\frac{1}{x ^{2} + y ^{2}} \frac{d}{d x} (x^{2} + y^{2})

= \frac{1}{x ^{2} + y ^{2}} \frac{d}{d x} (x^{2} + y^{2})

\frac{d}{d x} (x^{2} + y^{2}) = 2 x

= \frac{1}{x ^{2} + y ^{2}} \cdot 2 x

化简

\frac{1}{x ^{2} + y ^{2}} \cdot 2 x : \frac{2 x}{x ^{2} + y ^{2}}

= \frac{2 x}{x ^{2} + y ^{2}}

\frac{d}{d x} (e^{7 - x})

\frac{d ^{2}}{d x ^{2}} (9 t^{2} - 6 t + 3)

\frac{d}{d x} (ln (tanh (x)))

\int 4 cos^{3} (5 x) d x

\frac{\partial}{\partial y} (2 sin (y^{2}))