What is the solution for y*ln(x)*(dy}{dx}=(\frac{y+1)/x)^2 ?

The solution for y*ln(x)*(dy}{dx}=(\frac{y+1)/x)^2 is y=-1-1/(\W(-(1){e^{\frac{c_{1}x-1)/x}})}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

yln(x)(dy}{dx}=(\frac{y+1)/x)^2

y \cdot ln (x) \cdot \frac{d y}{d x} = (\frac{y + 1}{x})^{2}

y = - 1 - \frac{1}{W ( - \frac{1}{e ^{\frac{c _{1} x - 1}{x}}} )}

Solution steps

y \cdot ln (x) \cdot \frac{d y}{d x} = (\frac{y + 1}{x})^{2}

Solve Bernoulli ODE:

y = - 1 - \frac{1}{W ( - \frac{1}{e ^{\frac{c _{1} x - 1}{x}}} )}

y = - 1 - \frac{1}{W ( - \frac{1}{e ^{\frac{c _{1} x - 1}{x}}} )}

What is the solution for y*ln(x)*(dy}{dx}=(\frac{y+1)/x)^2 ?
The solution for y*ln(x)*(dy}{dx}=(\frac{y+1)/x)^2 is y=-1-1/(\W(-(1){e^{\frac{c_{1}x-1)/x}})}