What is the tangent of \sqrt[5]{x} ?

The tangent of \sqrt[5]{x} is y= 1/(5a_{0)^{4/5}}x+\sqrt[5]{a_{0}}-(a_{0}^{1/5})/5

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tangent of \sqrt[5]{x}

tangent of

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

Find the slope of

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = \frac{1}{5 a _{0}^{\frac{4}{5}}}

Find the line with slope m=

\frac{1}{5 a _{0}^{\frac{4}{5}}}

and passing through

What is the tangent of \sqrt[5]{x} ?
The tangent of \sqrt[5]{x} is y= 1/(5a_{0)^{4/5}}x+\sqrt[5]{a_{0}}-(a_{0}^{1/5})/5