What is the solution for (dy}{dx}=\frac{(x-1))/y ?

The solution for (dy}{dx}=\frac{(x-1))/y is y=sqrt(x^2-2x+c_{1)},y=-sqrt(x^2-2x+c_{1)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

(dy}{dx}=\frac{(x-1))/y

\frac{d y}{d x} = \frac{( x - 1 )}{y}

y = x^{2} - 2 x + c_{1}, y = - x^{2} - 2 x + c_{1}

Solution steps

\frac{d y}{d x} = \frac{( x - 1 )}{y}

Solve separable ODE:

y = x^{2} - 2 x + c_{1}, y = - x^{2} - 2 x + c_{1}

y = x^{2} - 2 x + c_{1}, y = - x^{2} - 2 x + c_{1}

What is the solution for (dy}{dx}=\frac{(x-1))/y ?
The solution for (dy}{dx}=\frac{(x-1))/y is y=sqrt(x^2-2x+c_{1)},y=-sqrt(x^2-2x+c_{1)}