What is the solution for y(1+xy)dx+(2y-x)dy=0 ?

The solution for y(1+xy)dx+(2y-x)dy=0 is y=-x/(2\W(-(x){2e^{\frac{-x^2+c_{1})/4}})}

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y(1+xy)dx+(2y-x)dy=0

y (1 + x y) d x + (2 y - x) d y = 0

y = - \frac{x}{2 W ( - \frac{x}{2 e ^{\frac{- x ^{2} + c _{1}}{4}}} )}

Solution steps

y (1 + x y) d x + (2 y - x) d y = 0

Solve using substitution:

y = - \frac{x}{2 W ( - \frac{x}{2 e ^{\frac{- x ^{2} + c _{1}}{4}}} )}

y = - \frac{x}{2 W ( - \frac{x}{2 e ^{\frac{- x ^{2} + c _{1}}{4}}} )}

What is the solution for y(1+xy)dx+(2y-x)dy=0 ?
The solution for y(1+xy)dx+(2y-x)dy=0 is y=-x/(2\W(-(x){2e^{\frac{-x^2+c_{1})/4}})}