What is the solution for f^'(x)=f(x)(1-f(x)) ?

The solution for f^'(x)=f(x)(1-f(x)) is f(x)=-(e^{x+c_{1}})/(1-e^{x+c_{1)}}

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f^'(x)=f(x)(1-f(x))

f^{^{'}} (x) = f (x) (1 - f (x))

f (x) = - \frac{e ^{x + c_{1}}}{1 - e ^{x + c_{1}}}

Solution steps

f^{'} (x) = f (x) (1 - f (x))

Solve separable ODE:

f (x) = - \frac{e ^{x + c_{1}}}{1 - e ^{x + c_{1}}}

f (x) = - \frac{e ^{x + c_{1}}}{1 - e ^{x + c_{1}}}

What is the solution for f^'(x)=f(x)(1-f(x)) ?
The solution for f^'(x)=f(x)(1-f(x)) is f(x)=-(e^{x+c_{1}})/(1-e^{x+c_{1)}}