(9x+3)+(9y-9)y^'=0

解

(9 x + 3) + (9 y - 9) y^{^{'}} = 0

y = \frac{6 + 36 - 12 ( - c _{1} + 2 x + 3 x ^{2} )}{6}, y = \frac{6 - 36 - 12 ( - c _{1} + 2 x + 3 x ^{2} )}{6}

解答ステップ

(9 x + 3) + (9 y - 9) y^{'} (x) = 0

分離可能 ODE を解く:

y = \frac{6 + 36 - 12 ( - c _{1} + 2 x + 3 x ^{2} )}{6}, y = \frac{6 - 36 - 12 ( - c _{1} + 2 x + 3 x ^{2} )}{6}

y = \frac{6 + 36 - 12 ( - c _{1} + 2 x + 3 x ^{2} )}{6}, y = \frac{6 - 36 - 12 ( - c _{1} + 2 x + 3 x ^{2} )}{6}