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Popular Calculus >

y^'=-y^2

Solution

y^{^{'}} = - y^{2}

Solution

y = - \frac{1}{- t + c _{1}}

Solution steps

y^{'} (t) = - y^{2}

Solve separable ODE:

y = - \frac{1}{- t + c _{1}}

y = - \frac{1}{- t + c _{1}}

Graph

Popular Examples

d/(dt)(Ate^{-4t})

\frac{d}{d t} (A t e^{- 4 t})

integral from 2 to 3 of (12)/(sqrt(3-x))

\int_{2}^{3} \frac{12}{3 - x} d x

integral from 0 to 1 of 7/(1+x^2)

\int_{0}^{1} \frac{7}{1 + x ^{2}} d x

inverse oflaplace (10s-3)/(s^2+4s+29)

in v erse l a pl a ce \frac{10 s - 3}{s ^{2} + 4 s + 29}

derivative of 1/(3-x)

d er i v a t i v e \frac{1}{3 - x}

Frequently Asked Questions (FAQ)

What is the solution for y^'=-y^2 ?
The solution for y^'=-y^2 is y=-1/(-t+c_{1)}