What is the derivative of 2x-3x^2 ?

The derivative of 2x-3x^2 is 2-6x

What is the first derivative of 2x-3x^2 ?

The first derivative of 2x-3x^2 is 2-6x

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\frac{d}{d x} (2 x - 3 x^{2})

2 - 6 x

Solution steps

\frac{d}{d x} (2 x - 3 x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x) - \frac{d}{d x} (3 x^{2})

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (3 x^{2}) = 6 x

= 2 - 6 x

What is the derivative of 2x-3x^2 ?
The derivative of 2x-3x^2 is 2-6x
What is the first derivative of 2x-3x^2 ?
The first derivative of 2x-3x^2 is 2-6x