What is the derivative of 4x^3+3x^2-6x+1 ?

The derivative of 4x^3+3x^2-6x+1 is 12x^2+6x-6

What is the first derivative of 4x^3+3x^2-6x+1 ?

The first derivative of 4x^3+3x^2-6x+1 is 12x^2+6x-6

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\frac{d}{d x} (4 x^{3} + 3 x^{2} - 6 x + 1)

12 x^{2} + 6 x - 6

Solution steps

\frac{d}{d x} (4 x^{3} + 3 x^{2} - 6 x + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4 x^{3}) + \frac{d}{d x} (3 x^{2}) - \frac{d}{d x} (6 x) + \frac{d}{d x} (1)

\frac{d}{d x} (4 x^{3}) = 12 x^{2}

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (6 x) = 6

\frac{d}{d x} (1) = 0

= 12 x^{2} + 6 x - 6 + 0

Simplify

= 12 x^{2} + 6 x - 6

What is the derivative of 4x^3+3x^2-6x+1 ?
The derivative of 4x^3+3x^2-6x+1 is 12x^2+6x-6
What is the first derivative of 4x^3+3x^2-6x+1 ?
The first derivative of 4x^3+3x^2-6x+1 is 12x^2+6x-6