What is inverse oflaplace (1.5)/(((s+1))) ?

The answer to inverse oflaplace (1.5)/(((s+1))) is 1.5e^{-t}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

inverse oflaplace (1.5)/(((s+1)))

inverse laplace

\frac{1.5}{( ( s + 1 ) )}

1.5 e^{- t}

Solution steps

L^{- 1} {\frac{1.5}{( ( s + 1 ) )}}

= L^{- 1} {1.5 \cdot \frac{1}{s + 1}}

Use the constant multiplication property of Inverse Laplace Transform:

For function

f (t)

and constant

a : L^{- 1} {a \cdot f (t)} = a \cdot L^{- 1} {f (t)}

= 1.5 L^{- 1} {\frac{1}{s + 1}}

Use Inverse Laplace Transform table:

L^{- 1} {\frac{1}{s - a}} = e^{a t}

L^{- 1} {\frac{1}{s + 1}} = e^{- t}

= 1.5 e^{- t}

What is inverse oflaplace (1.5)/(((s+1))) ?
The answer to inverse oflaplace (1.5)/(((s+1))) is 1.5e^{-t}