What is the solution for (2y^2+6x)dx+(2xy)dy=0 ?

The solution for (2y^2+6x)dx+(2xy)dy=0 is y=(sqrt(-2x^3+c_{1)})/x ,y=-(sqrt(-2x^3+c_{1)})/x

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(2y^2+6x)dx+(2xy)dy=0

(2 y^{2} + 6 x) d x + (2 x y) d y = 0

y = \frac{- 2 x ^{3} + c _{1}}{x}, y = - \frac{- 2 x ^{3} + c _{1}}{x}

Solution steps

(2 y^{2} + 6 x) d x + (2 x y) d y = 0

Solve Bernoulli ODE:

y = \frac{- 2 x ^{3} + c _{1}}{x}, y = - \frac{- 2 x ^{3} + c _{1}}{x}

y = \frac{- 2 x ^{3} + c _{1}}{x}, y = - \frac{- 2 x ^{3} + c _{1}}{x}

What is the solution for (2y^2+6x)dx+(2xy)dy=0 ?
The solution for (2y^2+6x)dx+(2xy)dy=0 is y=(sqrt(-2x^3+c_{1)})/x ,y=-(sqrt(-2x^3+c_{1)})/x