What is the derivative of \sqrt[5]{x^2}-2/x ?

The derivative of \sqrt[5]{x^2}-2/x is (2x)/(5(x^2)^{4/5)}+2/(x^2)

What is the first derivative of \sqrt[5]{x^2}-2/x ?

The first derivative of \sqrt[5]{x^2}-2/x is (2x)/(5(x^2)^{4/5)}+2/(x^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

derivative of

\frac{2 x}{5 ( x ^{2} ) ^{\frac{4}{5}}} + \frac{2}{x ^{2}}

Solution steps

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

\frac{d}{d x} (\frac{2}{x}) = - \frac{2}{x ^{2}}

= \frac{2 x}{5 ( x ^{2} ) ^{\frac{4}{5}}} - (- \frac{2}{x ^{2}})

Simplify

= \frac{2 x}{5 ( x ^{2} ) ^{\frac{4}{5}}} + \frac{2}{x ^{2}}

What is the derivative of \sqrt[5]{x^2}-2/x ?
The derivative of \sqrt[5]{x^2}-2/x is (2x)/(5(x^2)^{4/5)}+2/(x^2)
What is the first derivative of \sqrt[5]{x^2}-2/x ?
The first derivative of \sqrt[5]{x^2}-2/x is (2x)/(5(x^2)^{4/5)}+2/(x^2)