What is the tangent of x^2+y^2=17,(4,-1) ?

The tangent of x^2+y^2=17,(4,-1) is y=4x-17

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tangent of x^2+y^2=17,(4,-1)

tangent of

x^{2} + y^{2} = 17, (4, - 1)

y = 4 x - 17

Solution steps

Find the slope of

x^{2} + y^{2} = 17 : \frac{d y}{d x} = - \frac{x}{y}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 4

Find the line with slope m=

4

and passing through

(4, - 1) : y = 4 x - 17

y = 4 x - 17

What is the tangent of x^2+y^2=17,(4,-1) ?
The tangent of x^2+y^2=17,(4,-1) is y=4x-17