What is the limit as x approaches 9 of ((16+sqrt(x)))/(sqrt(16+x)) ?

The limit as x approaches 9 of ((16+sqrt(x)))/(sqrt(16+x)) is 19/5

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limit as x approaches 9 of ((16+sqrt(x)))/(sqrt(16+x))

x \to 9 lim (\frac{( 16 + x )}{16 + x})

\frac{19}{5}

Decimal

3.8

Solution steps

x \to 9 lim (\frac{16 + x}{16 + x})

Plug in the value

x = 9

= \frac{16 + 9}{16 + 9}

Simplify

\frac{16 + 9}{16 + 9} : \frac{19}{5}

= \frac{19}{5}

What is the limit as x approaches 9 of ((16+sqrt(x)))/(sqrt(16+x)) ?
The limit as x approaches 9 of ((16+sqrt(x)))/(sqrt(16+x)) is 19/5