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Popular Calculus >

integral from-1 to 4 of (6x-9)

Solution

\int_{- 1}^{4} (6 x - 9) d x

Solution

0

Solution steps

\int_{- 1}^{4} 6 x - 9 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{4} 6 x d x - \int_{- 1}^{4} 9 d x

\int_{- 1}^{4} 6 x d x = 45

\int_{- 1}^{4} 9 d x = 45

= 45 - 45

Simplify

= 0

Graph

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Frequently Asked Questions (FAQ)

What is the integral from-1 to 4 of (6x-9) ?
The integral from-1 to 4 of (6x-9) is 0