What is the tangent of x^6+y^2=2,(1,-1) ?

The tangent of x^6+y^2=2,(1,-1) is y=3x-4

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tangent of x^6+y^2=2,(1,-1)

tangent of

x^{6} + y^{2} = 2, (1, - 1)

y = 3 x - 4

Solution steps

Find the slope of

x^{6} + y^{2} = 2 : \frac{d y}{d x} = - \frac{3 x ^{5}}{y}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 3

Find the line with slope m=

3

and passing through

(1, - 1) : y = 3 x - 4

y = 3 x - 4

What is the tangent of x^6+y^2=2,(1,-1) ?
The tangent of x^6+y^2=2,(1,-1) is y=3x-4