What is the derivative of |x^2-3x+2| ?

The derivative of |x^2-3x+2| is ((x^2-3x+2)(2x-3))/(|x^2-3x+2|)

What is the first derivative of |x^2-3x+2| ?

The first derivative of |x^2-3x+2| is ((x^2-3x+2)(2x-3))/(|x^2-3x+2|)

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\frac{d}{d x} (x^{2} - 3 x + 2)

\frac{( x ^{2} - 3 x + 2 ) ( 2 x - 3 )}{∣ x ^{2} - 3 x + 2 ∣}

Solution steps

\frac{d}{d x} (x^{2} - 3 x + 2)

Apply the chain rule:

\frac{x ^{2} - 3 x + 2}{∣ ( x ^{2} - 3 x + 2 ) ∣} \frac{d}{d x} (x^{2} - 3 x + 2)

= \frac{x ^{2} - 3 x + 2}{∣ ( x ^{2} - 3 x + 2 ) ∣} \frac{d}{d x} (x^{2} - 3 x + 2)

\frac{d}{d x} (x^{2} - 3 x + 2) = 2 x - 3

= \frac{x ^{2} - 3 x + 2}{∣ ( x ^{2} - 3 x + 2 ) ∣} (2 x - 3)

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( x ^{2} - 3 x + 2 ) ( 2 x - 3 )}{∣ x ^{2} - 3 x + 2 ∣}

What is the derivative of |x^2-3x+2| ?
The derivative of |x^2-3x+2| is ((x^2-3x+2)(2x-3))/(|x^2-3x+2|)
What is the first derivative of |x^2-3x+2| ?
The first derivative of |x^2-3x+2| is ((x^2-3x+2)(2x-3))/(|x^2-3x+2|)