What is the tangent of f(x)= 2/(x+1),\at x=3,y=1 ?

The tangent of f(x)= 2/(x+1),\at x=3,y=1 is y=-1/8 x+7/8

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tangent of f(x)= 2/(x+1),\at x=3,y=1

tangent of

f (x) = \frac{2}{x + 1}, at x = 3, y = 1

y = - \frac{1}{8} x + \frac{7}{8}

Solution steps

Find the tangent point:

(3, \frac{1}{2})

Find the slope of

f (x) = \frac{2}{x + 1} : \frac{df ( x )}{d x} = - \frac{2}{( x + 1 ) ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - \frac{1}{8}

Find the line with slope m=

- \frac{1}{8}

and passing through

(3, \frac{1}{2}) : y = - \frac{1}{8} x + \frac{7}{8}

y = - \frac{1}{8} x + \frac{7}{8}

What is the tangent of f(x)= 2/(x+1),\at x=3,y=1 ?
The tangent of f(x)= 2/(x+1),\at x=3,y=1 is y=-1/8 x+7/8