What is the tangent of f(x)=2x^2+10x+9,\at x=-3 ?

The tangent of f(x)=2x^2+10x+9,\at x=-3 is y=-2x-9

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tangent of f(x)=2x^2+10x+9,\at x=-3

tangent of

f (x) = 2 x^{2} + 10 x + 9, at x = - 3

y = - 2 x - 9

Solution steps

Find the tangent point:

(- 3, - 3)

Find the slope of

f (x) = 2 x^{2} + 10 x + 9 : \frac{df ( x )}{d x} = 4 x + 10

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 2

Find the line with slope m=

- 2

and passing through

(- 3, - 3) : y = - 2 x - 9

y = - 2 x - 9

What is the tangent of f(x)=2x^2+10x+9,\at x=-3 ?
The tangent of f(x)=2x^2+10x+9,\at x=-3 is y=-2x-9