What is the integral from-1 to 2 of 2^x ?

The integral from-1 to 2 of 2^x is 7/(2ln(2))

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integral from-1 to 2 of 2^x

\int_{- 1}^{2} 2^{x} d x

\frac{7}{2 ln ( 2 )}

Decimal

5.04943 \dots

Solution steps

\int_{- 1}^{2} 2^{x} d x

\int a^{x} d x = \frac{a ^{x}}{ln a}

= [\frac{2 ^{x}}{ln ( 2 )}]_{- 1}^{2}

Compute the boundaries:

\frac{7}{2 ln ( 2 )}

= \frac{7}{2 ln ( 2 )}

What is the integral from-1 to 2 of 2^x ?
The integral from-1 to 2 of 2^x is 7/(2ln(2))