What is the integral of (2x)/(k^2) ?

The integral of (2x)/(k^2) is (x^2)/(k^2)+C

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integral of (2x)/(k^2)

\int \frac{2 x}{k ^{2}} d x

\frac{x ^{2}}{k ^{2}} + C

Solution steps

\int \frac{2 x}{k ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{2}{k ^{2}} \cdot \int x d x

Apply the Power Rule

= \frac{2}{k ^{2}} \cdot \frac{x ^{2}}{2}

Simplify

\frac{2}{k ^{2}} \cdot \frac{x ^{2}}{2} : \frac{x ^{2}}{k ^{2}}

= \frac{x ^{2}}{k ^{2}}

Add a constant to the solution

= \frac{x ^{2}}{k ^{2}} + C

What is the integral of (2x)/(k^2) ?
The integral of (2x)/(k^2) is (x^2)/(k^2)+C