What is the derivative of 7(sin(x^2)+2x^2cos(x^2)) ?

The derivative of 7(sin(x^2)+2x^2cos(x^2)) is 7(6xcos(x^2)-4x^3sin(x^2))

What is the first derivative of 7(sin(x^2)+2x^2cos(x^2)) ?

The first derivative of 7(sin(x^2)+2x^2cos(x^2)) is 7(6xcos(x^2)-4x^3sin(x^2))

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derivative of

7 (sin (x^{2}) + 2 x^{2} cos (x^{2}))

7 (6 x cos (x^{2}) - 4 x^{3} sin (x^{2}))

Solution steps

\frac{d}{d x} (7 (sin (x^{2}) + 2 x^{2} cos (x^{2})))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 7 \frac{d}{d x} (sin (x^{2}) + 2 x^{2} cos (x^{2}))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= 7 (\frac{d}{d x} (sin (x^{2})) + \frac{d}{d x} (2 x^{2} cos (x^{2})))

\frac{d}{d x} (sin (x^{2})) = cos (x^{2}) \cdot 2 x

\frac{d}{d x} (2 x^{2} cos (x^{2})) = 2 (2 x cos (x^{2}) - 2 x^{3} sin (x^{2}))

= 7 (cos (x^{2}) \cdot 2 x + 2 (2 x cos (x^{2}) - 2 x^{3} sin (x^{2})))

Expand

cos (x^{2}) \cdot 2 x + 2 (2 x cos (x^{2}) - 2 x^{3} sin (x^{2})) : 6 x cos (x^{2}) - 4 x^{3} sin (x^{2})

= 7 (6 x cos (x^{2}) - 4 x^{3} sin (x^{2}))

What is the derivative of 7(sin(x^2)+2x^2cos(x^2)) ?
The derivative of 7(sin(x^2)+2x^2cos(x^2)) is 7(6xcos(x^2)-4x^3sin(x^2))
What is the first derivative of 7(sin(x^2)+2x^2cos(x^2)) ?
The first derivative of 7(sin(x^2)+2x^2cos(x^2)) is 7(6xcos(x^2)-4x^3sin(x^2))