What is (\partial)/(\partial x)(2xyz^2-192) ?

The answer to (\partial)/(\partial x)(2xyz^2-192) is 2yz^2

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(\partial)/(\partial x)(2xyz^2-192)

\frac{\partial}{\partial x} (2 x y z^{2} - 192)

2 y z^{2}

Solution steps

\frac{\partial}{\partial x} (2 x y z^{2} - 192)

Treat

y, z

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (2 x y z^{2}) - \frac{\partial}{\partial x} (192)

\frac{\partial}{\partial x} (2 x y z^{2}) = 2 y z^{2}

\frac{\partial}{\partial x} (192) = 0

= 2 y z^{2} - 0

Simplify

= 2 y z^{2}

What is (\partial)/(\partial x)(2xyz^2-192) ?
The answer to (\partial)/(\partial x)(2xyz^2-192) is 2yz^2