integral of (2x^5-4sqrt(x)+8x)/x

Lösung

\int \frac{2 x ^{5} - 4 x + 8 x}{x} d x

\frac{2 x ^{5}}{5} - 8 x + 8 x + C

Schritte zur Lösung

\int \frac{2 x ^{5} - 4 x + 8 x}{x} d x

Multipliziere aus

\frac{2 x ^{5} - 4 x + 8 x}{x} : 2 x^{4} - \frac{4}{x} + 8

= \int 2 x^{4} - \frac{4}{x} + 8 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 2 x^{4} d x - \int \frac{4}{x} d x + \int 8 d x

\int 2 x^{4} d x = \frac{2 x ^{5}}{5}

\int \frac{4}{x} d x = 8 x

\int 8 d x = 8 x

= \frac{2 x ^{5}}{5} - 8 x + 8 x

Füge eine Konstante zur Lösung hinzu

= \frac{2 x ^{5}}{5} - 8 x + 8 x + C

ma c l a u r in ln (1 + e^{x})

\frac{d}{d x} (arcsin (2 x^{4}))

\int \frac{x ^{2} + 4 x + 7}{x ^{2} - 6 x + 5} d x

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\int (\frac{( x ^{3} + 1 ) ^{2}}{x ^{2}}) d x