What is the tangent of x^2+4xy+y^2=13,(2,1) ?

The tangent of x^2+4xy+y^2=13,(2,1) is y=-4/5 x+13/5

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tangent of x^2+4xy+y^2=13,(2,1)

tangent of

x^{2} + 4 x y + y^{2} = 13, (2, 1)

y = - \frac{4}{5} x + \frac{13}{5}

Solution steps

Find the slope of

x^{2} + 4 x y + y^{2} = 13 : \frac{d y}{d x} = - \frac{x + 2 y}{2 x + y}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - \frac{4}{5}

Find the line with slope m=

- \frac{4}{5}

and passing through

(2, 1) : y = - \frac{4}{5} x + \frac{13}{5}

y = - \frac{4}{5} x + \frac{13}{5}

What is the tangent of x^2+4xy+y^2=13,(2,1) ?
The tangent of x^2+4xy+y^2=13,(2,1) is y=-4/5 x+13/5