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Popular Calculus >

y^'=x^2-2

Solution

y^{^{'}} = x^{2} - 2

Solution

y = \frac{x ^{3}}{3} - 2 x + c_{1}

Solution steps

y^{'} (x) = x^{2} - 2

If

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int x^{2} - 2 d x

\int x^{2} - 2 d x = \frac{x ^{3}}{3} - 2 x + c_{1}

y = \frac{x ^{3}}{3} - 2 x + c_{1}

Graph

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Frequently Asked Questions (FAQ)

What is the solution for y^'=x^2-2 ?
The solution for y^'=x^2-2 is y=(x^3)/3-2x+c_{1}