What is (\partial)/(\partial y)(x-1/(y^2)) ?

The answer to (\partial)/(\partial y)(x-1/(y^2)) is 2/(y^3)

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(\partial)/(\partial y)(x-1/(y^2))

\frac{\partial}{\partial y} (x - \frac{1}{y ^{2}})

\frac{2}{y ^{3}}

Solution steps

\frac{\partial}{\partial y} (x - \frac{1}{y ^{2}})

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (x) - \frac{\partial}{\partial y} (\frac{1}{y ^{2}})

\frac{\partial}{\partial y} (x) = 0

\frac{\partial}{\partial y} (\frac{1}{y ^{2}}) = - \frac{2}{y ^{3}}

= 0 - (- \frac{2}{y ^{3}})

Simplify

= \frac{2}{y ^{3}}

What is (\partial)/(\partial y)(x-1/(y^2)) ?
The answer to (\partial)/(\partial y)(x-1/(y^2)) is 2/(y^3)