What is the solution for (dy)/(dx)=5y^2-y/x ?

The solution for (dy)/(dx)=5y^2-y/x is y= 1/(x(-5ln(x)+c_{1))}

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(dy)/(dx)=5y^2-y/x

\frac{d y}{d x} = 5 y^{2} - \frac{y}{x}

y = \frac{1}{x ( - 5 ln ( x ) + c _{1} )}

Solution steps

\frac{d y}{d x} = 5 y^{2} - \frac{y}{x}

Solve Bernoulli ODE:

y = \frac{1}{x ( - 5 ln ( x ) + c _{1} )}

y = \frac{1}{x ( - 5 ln ( x ) + c _{1} )}

What is the solution for (dy)/(dx)=5y^2-y/x ?
The solution for (dy)/(dx)=5y^2-y/x is y= 1/(x(-5ln(x)+c_{1))}