What is the tangent of f(x)=2x^2-3x,\at x=4 ?

The tangent of f(x)=2x^2-3x,\at x=4 is y=13x-32

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tangent of f(x)=2x^2-3x,\at x=4

tangent of

f (x) = 2 x^{2} - 3 x, at x = 4

y = 13 x - 32

Solution steps

Find the tangent point:

(4, 20)

Find the slope of

f (x) = 2 x^{2} - 3 x : \frac{df ( x )}{d x} = 4 x - 3

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 13

Find the line with slope m=

13

and passing through

(4, 20) : y = 13 x - 32

y = 13 x - 32

What is the tangent of f(x)=2x^2-3x,\at x=4 ?
The tangent of f(x)=2x^2-3x,\at x=4 is y=13x-32