What is the tangent of 6/((4x+1)) ?

The tangent of 6/((4x+1)) is y=-(24)/((4a_{0)+1)^2}x+(48a_{0}+6)/((4a_{0)+1)^2}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

tangent of 6/((4x+1))

tangent of

\frac{6}{( 4 x + 1 )}

y = - \frac{24}{( 4 a _{0} + 1 ) ^{2}} x + \frac{48 a _{0} + 6}{( 4 a _{0} + 1 ) ^{2}}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, \frac{6}{4 a _{0} + 1})

Find the slope of

y = \frac{6}{4 x + 1} : \frac{d y}{d x} = - \frac{24}{( 4 x + 1 ) ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - \frac{24}{( 4 a _{0} + 1 ) ^{2}}

Find the line with slope m=

- \frac{24}{( 4 a _{0} + 1 ) ^{2}}

and passing through

(a_{0}, \frac{6}{4 a _{0} + 1}) : y = - \frac{24}{( 4 a _{0} + 1 ) ^{2}} x + \frac{48 a _{0} + 6}{( 4 a _{0} + 1 ) ^{2}}

y = - \frac{24}{( 4 a _{0} + 1 ) ^{2}} x + \frac{48 a _{0} + 6}{( 4 a _{0} + 1 ) ^{2}}

What is the tangent of 6/((4x+1)) ?
The tangent of 6/((4x+1)) is y=-(24)/((4a_{0)+1)^2}x+(48a_{0}+6)/((4a_{0)+1)^2}