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Popular Calculus >

(x+1)y^'=xy

Solution

(x + 1) y^{^{'}} = x y

Solution

y = \frac{e ^{x + 1 + c_{1}}}{x + 1}

Solution steps

(x + 1) y^{'} (x) = x y

Solve separable ODE:

y = \frac{e ^{x + 1 + c_{1}}}{x + 1}

y = \frac{e ^{x + 1 + c_{1}}}{x + 1}

Graph

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Frequently Asked Questions (FAQ)

What is the solution for (x+1)y^'=xy ?
The solution for (x+1)y^'=xy is y=(e^{x+1+c_{1}})/(x+1)