What is the tangent of f(x)=5x-4x^2,(-3,-51) ?

The tangent of f(x)=5x-4x^2,(-3,-51) is y=29x+36

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tangent of f(x)=5x-4x^2,(-3,-51)

tangent of

f (x) = 5 x - 4 x^{2}, (- 3, - 51)

y = 29 x + 36

Solution steps

Find the slope of

f (x) = 5 x - 4 x^{2} : \frac{df ( x )}{d x} = 5 - 8 x

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 29

Find the line with slope m=

29

and passing through

(- 3, - 51) : y = 29 x + 36

y = 29 x + 36

What is the tangent of f(x)=5x-4x^2,(-3,-51) ?
The tangent of f(x)=5x-4x^2,(-3,-51) is y=29x+36