What is laplacetransform-4(t-1) ?

The answer to laplacetransform-4(t-1) is -4/(s^2)+4/s

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laplacetransform-4(t-1)

laplace transform

- 4 (t - 1)

- \frac{4}{s ^{2}} + \frac{4}{s}

Solution steps

L {- 4 (t - 1)}

Expand

- 4 (t - 1) : - 4 t + 4

= L {- 4 t + 4}

Use the linearity property of Laplace Transform:

For functions

f (t), g (t)

and constants

a, b : L {a \cdot f (t) + b \cdot g (t)} = a \cdot L {f (t)} + b \cdot L {g (t)}

= - 4 L {t} + L {4}

L {t} : \frac{1}{s ^{2}}

L {4} : \frac{4}{s}

= - 4 \cdot \frac{1}{s ^{2}} + \frac{4}{s}

Refine

- 4 \frac{1}{s ^{2}} + \frac{4}{s} : - \frac{4}{s ^{2}} + \frac{4}{s}

= - \frac{4}{s ^{2}} + \frac{4}{s}

What is laplacetransform-4(t-1) ?
The answer to laplacetransform-4(t-1) is -4/(s^2)+4/s