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Beliebt Rechnen >

y^{''}+2y^'+2y=0,y(pi/4)=2,y^'(pi/4)=-2

Lösung

y^{^{''}} + 2 y^{^{'}} + 2 y = 0, y (\frac{π}{4}) = 2, y^{^{'}} (\frac{π}{4}) = - 2

Lösung

y = e^{- t} (2 e^{\frac{π}{4}} cos (t) + 2 e^{\frac{π}{4}} sin (t))

Schritte zur Lösung

y^{''} (t) + 2 y^{'} (t) + 2 y = 0

Solve linear ODE:

y = e^{- t} (2 e^{\frac{π}{4}} cos (t) + 2 e^{\frac{π}{4}} sin (t))

y = e^{- t} (2 e^{\frac{π}{4}} cos (t) + 2 e^{\frac{π}{4}} sin (t))

Graph

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