What is the tangent of f(x)=-3+(x+4)^2,\at x=-5 ?

The tangent of f(x)=-3+(x+4)^2,\at x=-5 is y=-2x-12

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tangent of f(x)=-3+(x+4)^2,\at x=-5

tangent of

f (x) = - 3 + (x + 4)^{2}, at x = - 5

y = - 2 x - 12

Solution steps

Find the tangent point:

(- 5, - 2)

Find the slope of

f (x) = - 3 + (x + 4)^{2} : \frac{df ( x )}{d x} = 2 x + 8

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 2

Find the line with slope m=

- 2

and passing through

(- 5, - 2) : y = - 2 x - 12

y = - 2 x - 12

What is the tangent of f(x)=-3+(x+4)^2,\at x=-5 ?
The tangent of f(x)=-3+(x+4)^2,\at x=-5 is y=-2x-12